Jump to content
The Corroboree
Sign in to follow this  
Teljkon

Chambers inside 6 spheres around a point

Recommended Posts

dfdgdg

Edited by Teljkon

Share this post


Link to post
Share on other sites

I think you've left out some vital information. Could you show the image, and perhaps explain exactly what you mean by this chambers thing?

Share this post


Link to post
Share on other sites

sdfs

Edited by Teljkon

Share this post


Link to post
Share on other sites

I still don't understand what you are asking?

If the side of the cube has a lenth of 2D, then if the spheres are allowed to overlap, you can fit an infinite number. If they are not allowed to overlap, the you can only fit two. I realise this is not what you are asking though...

EDIT: OK so now I think you are asking:

"If I have 6 spheres of equal radius, and the spheres are spaced evenly such that the surface of each sphere intersects the same point in space, how many separate volumes will I create as defined by the surfaces of the 6 original spheres?"

Am I close?

Edited by Alice

Share this post


Link to post
Share on other sites

In which case I would guess 26.

4 spheres along x and y overlap to form 8 chambers. Bring in the 5th sphere along z, which will overlap with at least some of each of the 8 chambers previously formed to form 8 new chambers. Plus the "leftover" part of sphere 5 (i.e. that which is not close to the point, the biggest bit). That's 17. Bring in sphere 6 from the other end of z. That adds another 8, plus the bit leftover. That's 26.

Share this post


Link to post
Share on other sites

I don't think whos surfaces intersect a point. More like whos volumes contain said point.

I'll do a sketch up and see what I can see.

EDIT: This would be much easier if I had semitransparent spheres that I could push through each other and manipulate shade and light levels with ease. As a pen-and-paper problem it's hard for me to get my head around. I'm sure there is a mathematical solution but i don't know it.

Edited by Sheather

Share this post


Link to post
Share on other sites

That function should really have a -1 at the end to determine the number of enclosed spaces, as that equation appears to be based off number of sections including surrounding space, so the pattern would be 1,3,7,15,29 etc.

Share this post


Link to post
Share on other sites

That function should really have a -1 at the end to determine the number of enclosed spaces, as that equation appears to be based off number of sections including surrounding space, so the pattern would be 1,3,7,15,29 etc.

 

yep. the sphere defines a closed set in R^3 so it intersects R^3 into 2 spaces. minus 1 to count out the surrounding space.

Share this post


Link to post
Share on other sites
6 spheres that are centered around a point

1.

:D

But in all seriousness, I think qualia got it.

  • Like 1

Share this post


Link to post
Share on other sites

ssdfsfs

Edited by Teljkon

Share this post


Link to post
Share on other sites

Does anyone know how many intersecting spheres would fit in a polytope then? :-P

6445739517_a2113c8ace_z.jpg

Share this post


Link to post
Share on other sites

Is that a fractal? It looks like the compartments approach 0 size as their centre approaches the middle of the construct, but I can see no way to be sure.

Share this post


Link to post
Share on other sites

nm. i see you were being facetious.

Edited by qualia

Share this post


Link to post
Share on other sites

Sorry I was indeed acting in a jocular fashion, people started talking about intersecting spheres in euclidean geometries and I'll polytope at ther drop of a hat.

It's a polytope Sheather (possibly a Cayley graph), there is a limit to the self similarity/iterations so it isn't a fractal... but polychoron/polytopes are dope imo.

  • Like 1

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
Sign in to follow this  

×